-(2/3)b=0

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Solution for -(2/3)b=0 equation: 



-(2/3)b=0



Domain of the equation: 3)b!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

-(+2/3)b=0

We multiply parentheses

-2b^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{-4}=0$

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