-(2/3)m-4=10

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Solution for -(2/3)m-4=10 equation: 



-(2/3)m-4=10

We move all terms to the left:

-(2/3)m-4-(10)=0



Domain of the equation: 3)m!=0

m!=0/1

m!=0

m∈R



We add all the numbers together, and all the variables

-(+2/3)m-4-10=0

We add all the numbers together, and all the variables

-(+2/3)m-14=0

We multiply parentheses

-2m^2-14=0

a = -2; b = 0; c = -14;
Δ = b2-4ac
Δ = 02-4·(-2)·(-14)
Δ = -112
Delta is less than zero, so there is no solution for the equation

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