-(2/3)p+(8/3)=-3p

Solution for -(2/3)p+(8/3)=-3p equation:

-(2/3)p+(8/3)=-3p

We move all terms to the left:

-(2/3)p+(8/3)-(-3p)=0


Domain of the equation: 3)p!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

-(+2/3)p-(-3p)+(+8/3)=0

We multiply parentheses

-2p^2-(-3p)+(+8/3)=0

We get rid of parentheses

-2p^2+3p+8/3=0

We multiply all the terms by the denominator


-2p^2*3+3p*3+8=0

Wy multiply elements

-6p^2+9p+8=0

a = -6; b = 9; c = +8;
Δ = b2-4ac
Δ = 92-4·(-6)·8
Δ = 273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{273}}{2*-6}=\frac{-9-\sqrt{273}}{-12}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{273}}{2*-6}=\frac{-9+\sqrt{273}}{-12}
$