-(2/3)x+(5/6)=(7/12)

Solution for -(2/3)x+(5/6)=(7/12) equation:

-(2/3)x+(5/6)=(7/12)

We move all terms to the left:

-(2/3)x+(5/6)-((7/12))=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(+2/3)x+(+5/6)-((+7/12))=0

We multiply parentheses

-2x^2+(+5/6)-((+7/12))=0

We get rid of parentheses

-2x^2+5/6-((+7/12))=0

We calculate fractions


-2x^2+()/()+()/()=0

We add all the numbers together, and all the variables

-2x^2+2=0

a = -2; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-2)·2
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*-2}=\frac{-4}{-4}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*-2}=\frac{4}{-4}
=-1
$