-(2b+10)+4b=2(b-5)

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Solution for -(2b+10)+4b=2(b-5) equation: 



-(2b+10)+4b=2(b-5)

We move all terms to the left:

-(2b+10)+4b-(2(b-5))=0

We add all the numbers together, and all the variables

4b-(2b+10)-(2(b-5))=0

We get rid of parentheses

4b-2b-(2(b-5))-10=0



We calculate terms in parentheses: -(2(b-5)), so:

2(b-5)

We multiply parentheses

2b-10

Back to the equation:

-(2b-10)



We add all the numbers together, and all the variables

2b-(2b-10)-10=0

We get rid of parentheses

2b-2b+10-10=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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