-(2b-5)+1=2+(2b+3)

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Solution for -(2b-5)+1=2+(2b+3) equation: 



-(2b-5)+1=2+(2b+3)

We move all terms to the left:

-(2b-5)+1-(2+(2b+3))=0

We get rid of parentheses

-2b-(2+(2b+3))+5+1=0



We calculate terms in parentheses: -(2+(2b+3)), so:

2+(2b+3)

determiningTheFunctionDomain
(2b+3)+2

We get rid of parentheses

2b+3+2

We add all the numbers together, and all the variables

2b+5

Back to the equation:

-(2b+5)



We add all the numbers together, and all the variables

-2b-(2b+5)+6=0

We get rid of parentheses

-2b-2b-5+6=0

We add all the numbers together, and all the variables

-4b+1=0

We move all terms containing b to the left, all other terms to the right

-4b=-1

b=-1/-4

b=1/4

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