-(2c-4)=3(c-2)

Solution for -(2c-4)=3(c-2) equation:

Simplifying
-1(2c + -4) = 3(c + -2)

Reorder the terms:
-1(-4 + 2c) = 3(c + -2)
(-4 * -1 + 2c * -1) = 3(c + -2)
(4 + -2c) = 3(c + -2)

Reorder the terms:
4 + -2c = 3(-2 + c)
4 + -2c = (-2 * 3 + c * 3)
4 + -2c = (-6 + 3c)

Solving
4 + -2c = -6 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
4 + -2c + -3c = -6 + 3c + -3c

Combine like terms: -2c + -3c = -5c
4 + -5c = -6 + 3c + -3c

Combine like terms: 3c + -3c = 0
4 + -5c = -6 + 0
4 + -5c = -6

Add '-4' to each side of the equation.
4 + -4 + -5c = -6 + -4

Combine like terms: 4 + -4 = 0
0 + -5c = -6 + -4
-5c = -6 + -4

Combine like terms: -6 + -4 = -10
-5c = -10

Divide each side by '-5'.
c = 2

Simplifying
c = 2