-(2d-1)+3(d+2)=7

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Solution for -(2d-1)+3(d+2)=7 equation: 



-(2d-1)+3(d+2)=7

We move all terms to the left:

-(2d-1)+3(d+2)-(7)=0

We multiply parentheses

-(2d-1)+3d+6-7=0

We get rid of parentheses

-2d+3d+1+6-7=0

We add all the numbers together, and all the variables

d=0

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