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-(2h+4)=5(h-1)+3
We move all terms to the left:
-(2h+4)-(5(h-1)+3)=0
We get rid of parentheses
-2h-(5(h-1)+3)-4=0
We calculate terms in parentheses: -(5(h-1)+3), so:We get rid of parentheses
5(h-1)+3
We multiply parentheses
5h-5+3
We add all the numbers together, and all the variables
5h-2
Back to the equation:
-(5h-2)
-2h-5h+2-4=0
We add all the numbers together, and all the variables
-7h-2=0
We move all terms containing h to the left, all other terms to the right
-7h=2
h=2/-7
h=-2/7
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