-(2k+-4)-3k=2(k+5)

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Solution for -(2k+-4)-3k=2(k+5) equation: 



-(2k+-4)-3k=2(k+5)

We move all terms to the left:

-(2k+-4)-3k-(2(k+5))=0

We add all the numbers together, and all the variables

-(2k-4)-3k-(2(k+5))=0

We add all the numbers together, and all the variables

-3k-(2k-4)-(2(k+5))=0

We get rid of parentheses

-3k-2k-(2(k+5))+4=0



We calculate terms in parentheses: -(2(k+5)), so:

2(k+5)

We multiply parentheses

2k+10

Back to the equation:

-(2k+10)



We add all the numbers together, and all the variables

-5k-(2k+10)+4=0

We get rid of parentheses

-5k-2k-10+4=0

We add all the numbers together, and all the variables

-7k-6=0

We move all terms containing k to the left, all other terms to the right

-7k=6

k=6/-7

k=-6/7

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