-(2n-4)-3(n-1)=17

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Solution for -(2n-4)-3(n-1)=17 equation: 



-(2n-4)-3(n-1)=17

We move all terms to the left:

-(2n-4)-3(n-1)-(17)=0

We multiply parentheses

-(2n-4)-3n+3-17=0

We get rid of parentheses

-2n-3n+4+3-17=0

We add all the numbers together, and all the variables

-5n-10=0

We move all terms containing n to the left, all other terms to the right

-5n=10

n=10/-5

n=-2

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