-(2r+4)=(6r+12)

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Solution for -(2r+4)=(6r+12) equation: 



-(2r+4)=(6r+12)

We move all terms to the left:

-(2r+4)-((6r+12))=0

We get rid of parentheses

-2r-((6r+12))-4=0



We calculate terms in parentheses: -((6r+12)), so:

(6r+12)

We get rid of parentheses

6r+12

Back to the equation:

-(6r+12)



We get rid of parentheses

-2r-6r-12-4=0

We add all the numbers together, and all the variables

-8r-16=0

We move all terms containing r to the left, all other terms to the right

-8r=16

r=16/-8

r=-2

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