-(2w+3)/5=-(w-2)/3

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Solution for -(2w+3)/5=-(w-2)/3 equation: 



-(2w+3)/5=-(w-2)/3

We move all terms to the left:

-(2w+3)/5-(-(w-2)/3)=0

We calculate fractions


(-2w)/()+(-(-(w-2)*5)/()=0



We calculate terms in parentheses: +(-(-(w-2)*5)/(), so:

-(-(w-2)*5)/(

We multiply all the terms by the denominator


-(-(w-2)*5)



We calculate terms in parentheses: -(-(w-2)*5), so:

-(w-2)*5

We multiply parentheses

-5w+10

Back to the equation:

-(-5w+10)



We get rid of parentheses

5w-10

Back to the equation:

+(5w-10)



We get rid of parentheses

(-2w)/()+5w-10=0

We multiply all the terms by the denominator


(-2w)+5w*()-10*()=0

We add all the numbers together, and all the variables

(-2w)+5w*()=0

We get rid of parentheses

-2w+5w*()=0

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