-(2x+1)=8(x+2)-7

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Solution for -(2x+1)=8(x+2)-7 equation: 



-(2x+1)=8(x+2)-7

We move all terms to the left:

-(2x+1)-(8(x+2)-7)=0

We get rid of parentheses

-2x-(8(x+2)-7)-1=0



We calculate terms in parentheses: -(8(x+2)-7), so:

8(x+2)-7

We multiply parentheses

8x+16-7

We add all the numbers together, and all the variables

8x+9

Back to the equation:

-(8x+9)



We get rid of parentheses

-2x-8x-9-1=0

We add all the numbers together, and all the variables

-10x-10=0

We move all terms containing x to the left, all other terms to the right

-10x=10

x=10/-10

x=-1

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