-(2x-1)(3x+5)=50-6x(x-3)

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Solution for -(2x-1)(3x+5)=50-6x(x-3) equation: 



-(2x-1)(3x+5)=50-6x(x-3)

We move all terms to the left:

-(2x-1)(3x+5)-(50-6x(x-3))=0

We multiply parentheses ..

-(+6x^2+10x-3x-5)-(50-6x(x-3))=0



We calculate terms in parentheses: -(50-6x(x-3)), so:

50-6x(x-3)

determiningTheFunctionDomain
-6x(x-3)+50

We multiply parentheses

-6x^2+18x+50

Back to the equation:

-(-6x^2+18x+50)



We get rid of parentheses

-6x^2+6x^2-10x+3x-18x+5-50=0

We add all the numbers together, and all the variables

-25x-45=0

We move all terms containing x to the left, all other terms to the right

-25x=45

x=45/-25

x=-1+4/5

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