-(2x-2)=4(x-2)+3x-2+2x+1

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Solution for -(2x-2)=4(x-2)+3x-2+2x+1 equation: 



-(2x-2)=4(x-2)+3x-2+2x+1

We move all terms to the left:

-(2x-2)-(4(x-2)+3x-2+2x+1)=0

We get rid of parentheses

-2x-(4(x-2)+3x-2+2x+1)+2=0



We calculate terms in parentheses: -(4(x-2)+3x-2+2x+1), so:

4(x-2)+3x-2+2x+1

determiningTheFunctionDomain
4(x-2)+3x+2x-2+1

We add all the numbers together, and all the variables

5x+4(x-2)-1

We multiply parentheses

5x+4x-8-1

We add all the numbers together, and all the variables

9x-9

Back to the equation:

-(9x-9)



We get rid of parentheses

-2x-9x+9+2=0

We add all the numbers together, and all the variables

-11x+11=0

We move all terms containing x to the left, all other terms to the right

-11x=-11

x=-11/-11

x=1

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