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-(2x-3)(5x+1)=0
We multiply parentheses ..
-(+10x^2+2x-15x-3)=0
We get rid of parentheses
-10x^2-2x+15x+3=0
We add all the numbers together, and all the variables
-10x^2+13x+3=0
a = -10; b = 13; c = +3;
Δ = b2-4ac
Δ = 132-4·(-10)·3
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-17}{2*-10}=\frac{-30}{-20} =1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+17}{2*-10}=\frac{4}{-20} =-1/5 $
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