-(2x-3)+x=1/3(4x+5)-8

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Solution for -(2x-3)+x=1/3(4x+5)-8 equation: 



-(2x-3)+x=1/3(4x+5)-8

We move all terms to the left:

-(2x-3)+x-(1/3(4x+5)-8)=0



Domain of the equation: 3(4x+5)-8)!=0

x∈R



We add all the numbers together, and all the variables

x-(2x-3)-(1/3(4x+5)-8)=0

We get rid of parentheses

x-2x-(1/3(4x+5)-8)+3=0

We multiply all the terms by the denominator


x*3(4x+5)-8)-2x*3(4x+5)-8)-(1+3*3(4x+5)-8)=0

We add all the numbers together, and all the variables

x*3(4x+5)-8)-2x*3(4x+5)-8)-(1+3*3(4x=0

Wy multiply elements

3x^2(4-8)-2x*3(4x+5)+3*3(4x-8)-(1=0

We add all the numbers together, and all the variables

3x^2(-4)-2x*3(4x+5)+3*3(4x-8)-(1=0

We add all the numbers together, and all the variables

3x^2(-4)-2x*3(4x+5)+3*3(4x-8)=0

Wy multiply elements

3x^2(-4)-6x^2(4+9x(4=0

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