-(2x-3)-(2x-5)+6=-3(x-1)-(4x+4)+3

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Solution for -(2x-3)-(2x-5)+6=-3(x-1)-(4x+4)+3 equation: 



-(2x-3)-(2x-5)+6=-3(x-1)-(4x+4)+3

We move all terms to the left:

-(2x-3)-(2x-5)+6-(-3(x-1)-(4x+4)+3)=0

We get rid of parentheses

-2x-2x-(-3(x-1)-(4x+4)+3)+3+5+6=0



We calculate terms in parentheses: -(-3(x-1)-(4x+4)+3), so:

-3(x-1)-(4x+4)+3

We multiply parentheses

-3x-(4x+4)+3+3

We get rid of parentheses

-3x-4x-4+3+3

We add all the numbers together, and all the variables

-7x+2

Back to the equation:

-(-7x+2)



We add all the numbers together, and all the variables

-4x-(-7x+2)+14=0

We get rid of parentheses

-4x+7x-2+14=0

We add all the numbers together, and all the variables

3x+12=0

We move all terms containing x to the left, all other terms to the right

3x=-12

x=-12/3

x=-4

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