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-(2x-4)+3(x-1)=2(x-1)-x-3
We move all terms to the left:
-(2x-4)+3(x-1)-(2(x-1)-x-3)=0
We multiply parentheses
-(2x-4)+3x-(2(x-1)-x-3)-3=0
We get rid of parentheses
-2x+3x-(2(x-1)-x-3)+4-3=0
We calculate terms in parentheses: -(2(x-1)-x-3), so:We add all the numbers together, and all the variables
2(x-1)-x-3
We add all the numbers together, and all the variables
-1x+2(x-1)-3
We multiply parentheses
-1x+2x-2-3
We add all the numbers together, and all the variables
x-5
Back to the equation:
-(x-5)
x-(x-5)+1=0
We get rid of parentheses
x-x+5+1=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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