-(2x-6)+5=x+3/2(-2x+8)

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Solution for -(2x-6)+5=x+3/2(-2x+8) equation: 



-(2x-6)+5=x+3/2(-2x+8)

We move all terms to the left:

-(2x-6)+5-(x+3/2(-2x+8))=0



Domain of the equation: 2(-2x+8))!=0

x∈R



We get rid of parentheses

-2x-(x+3/2(-2x+8))+6+5=0

We multiply all the terms by the denominator


-2x*2(-2x+8))-(x+6*2(-2x+8))+5*2(-2x+3+8))=0

We add all the numbers together, and all the variables

-2x*2(-2x+8))-(x+6*2(-2x+8))+5*2(-2x+11))=0

We add all the numbers together, and all the variables

-2x-2x*2(-2x+8))-(x+6*2(-2x+8))+5*2(=0

Wy multiply elements

-4x^2(-+24x^2(--2x=0

We use the square of the difference formula

-4x^2(-24x^2(+2x=0

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