-(2x-7)(2x+7)=-2(3x-5)(x-4)

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Solution for -(2x-7)(2x+7)=-2(3x-5)(x-4) equation: 



-(2x-7)(2x+7)=-2(3x-5)(x-4)

We move all terms to the left:

-(2x-7)(2x+7)-(-2(3x-5)(x-4))=0

We use the square of the difference formula

4x^2-(-2(3x-5)(x-4))+49=0

We multiply parentheses ..

4x^2-(-2(+3x^2-12x-5x+20))+49=0



We calculate terms in parentheses: -(-2(+3x^2-12x-5x+20)), so:

-2(+3x^2-12x-5x+20)

We multiply parentheses

-6x^2+24x+10x-40

We add all the numbers together, and all the variables

-6x^2+34x-40

Back to the equation:

-(-6x^2+34x-40)



We get rid of parentheses

4x^2+6x^2-34x+40+49=0

We add all the numbers together, and all the variables

10x^2-34x+89=0

a = 10; b = -34; c = +89;
Δ = b2-4ac
Δ = -342-4·10·89
Δ = -2404
Delta is less than zero, so there is no solution for the equation

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