-(2x-8)-(4x-4)+3=-4(x-7)-(7x+9)+4

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Solution for -(2x-8)-(4x-4)+3=-4(x-7)-(7x+9)+4 equation: 



-(2x-8)-(4x-4)+3=-4(x-7)-(7x+9)+4

We move all terms to the left:

-(2x-8)-(4x-4)+3-(-4(x-7)-(7x+9)+4)=0

We get rid of parentheses

-2x-4x-(-4(x-7)-(7x+9)+4)+8+4+3=0



We calculate terms in parentheses: -(-4(x-7)-(7x+9)+4), so:

-4(x-7)-(7x+9)+4

We multiply parentheses

-4x-(7x+9)+28+4

We get rid of parentheses

-4x-7x-9+28+4

We add all the numbers together, and all the variables

-11x+23

Back to the equation:

-(-11x+23)



We add all the numbers together, and all the variables

-6x-(-11x+23)+15=0

We get rid of parentheses

-6x+11x-23+15=0

We add all the numbers together, and all the variables

5x-8=0

We move all terms containing x to the left, all other terms to the right

5x=8

x=8/5

x=1+3/5

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