-(2y+3)(7y+1)=0

Solution for -(2y+3)(7y+1)=0 equation:

-(2y+3)(7y+1)=0

We multiply parentheses ..

-(+14y^2+2y+21y+3)=0

We get rid of parentheses

-14y^2-2y-21y-3=0

We add all the numbers together, and all the variables

-14y^2-23y-3=0

a = -14; b = -23; c = -3;
Δ = b2-4ac
Δ = -232-4·(-14)·(-3)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-19}{2*-14}=\frac{4}{-28}
=-1/7
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+19}{2*-14}=\frac{42}{-28}
=-1+1/2
$