-(2y+3)+(4y-3)=

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Solution for -(2y+3)+(4y-3)= equation:


Simplifying
-1(2y + 3) + (4y + -3) = 0

Reorder the terms:
-1(3 + 2y) + (4y + -3) = 0
(3 * -1 + 2y * -1) + (4y + -3) = 0
(-3 + -2y) + (4y + -3) = 0

Reorder the terms:
-3 + -2y + (-3 + 4y) = 0

Remove parenthesis around (-3 + 4y)
-3 + -2y + -3 + 4y = 0

Reorder the terms:
-3 + -3 + -2y + 4y = 0

Combine like terms: -3 + -3 = -6
-6 + -2y + 4y = 0

Combine like terms: -2y + 4y = 2y
-6 + 2y = 0

Solving
-6 + 2y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 2y = 0 + 6

Combine like terms: -6 + 6 = 0
0 + 2y = 0 + 6
2y = 0 + 6

Combine like terms: 0 + 6 = 6
2y = 6

Divide each side by '2'.
y = 3

Simplifying
y = 3

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