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-(2y-2)=2y-5-2y^2
We move all terms to the left:
-(2y-2)-(2y-5-2y^2)=0
We get rid of parentheses
2y^2-2y-2y+5+2=0
We add all the numbers together, and all the variables
2y^2-4y+7=0
a = 2; b = -4; c = +7;
Δ = b2-4ac
Δ = -42-4·2·7
Δ = -40
Delta is less than zero, so there is no solution for the equation
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