-(2z+4)=6z-3(2z+2)

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Solution for -(2z+4)=6z-3(2z+2) equation: 



-(2z+4)=6z-3(2z+2)

We move all terms to the left:

-(2z+4)-(6z-3(2z+2))=0

We get rid of parentheses

-2z-(6z-3(2z+2))-4=0



We calculate terms in parentheses: -(6z-3(2z+2)), so:

6z-3(2z+2)

We multiply parentheses

6z-6z-6

We add all the numbers together, and all the variables

-6

Back to the equation:

-(-6)



We add all the numbers together, and all the variables

-2z+2=0

We move all terms containing z to the left, all other terms to the right

-2z=-2

z=-2/-2

z=1

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