-(3+3x)=-2(x+4)-8

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Solution for -(3+3x)=-2(x+4)-8 equation: 



-(3+3x)=-2(x+4)-8

We move all terms to the left:

-(3+3x)-(-2(x+4)-8)=0

We add all the numbers together, and all the variables

-(3x+3)-(-2(x+4)-8)=0

We get rid of parentheses

-3x-(-2(x+4)-8)-3=0



We calculate terms in parentheses: -(-2(x+4)-8), so:

-2(x+4)-8

We multiply parentheses

-2x-8-8

We add all the numbers together, and all the variables

-2x-16

Back to the equation:

-(-2x-16)



We get rid of parentheses

-3x+2x+16-3=0

We add all the numbers together, and all the variables

-1x+13=0

We move all terms containing x to the left, all other terms to the right

-x=-13

x=-13/-1

x=+13

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