-(3+4a)=5(a-3)

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Solution for -(3+4a)=5(a-3) equation: 



-(3+4a)=5(a-3)

We move all terms to the left:

-(3+4a)-(5(a-3))=0

We add all the numbers together, and all the variables

-(4a+3)-(5(a-3))=0

We get rid of parentheses

-4a-(5(a-3))-3=0



We calculate terms in parentheses: -(5(a-3)), so:

5(a-3)

We multiply parentheses

5a-15

Back to the equation:

-(5a-15)



We get rid of parentheses

-4a-5a+15-3=0

We add all the numbers together, and all the variables

-9a+12=0

We move all terms containing a to the left, all other terms to the right

-9a=-12

a=-12/-9

a=1+1/3

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