-(3-2a)=3(a-11)

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Solution for -(3-2a)=3(a-11) equation: 



-(3-2a)=3(a-11)

We move all terms to the left:

-(3-2a)-(3(a-11))=0

We add all the numbers together, and all the variables

-(-2a+3)-(3(a-11))=0

We get rid of parentheses

2a-(3(a-11))-3=0



We calculate terms in parentheses: -(3(a-11)), so:

3(a-11)

We multiply parentheses

3a-33

Back to the equation:

-(3a-33)



We get rid of parentheses

2a-3a+33-3=0

We add all the numbers together, and all the variables

-1a+30=0

We move all terms containing a to the left, all other terms to the right

-a=-30

a=-30/-1

a=+30

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