-(3-2a)=3(a-11)

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Solution for -(3-2a)=3(a-11) equation:



-(3-2a)=3(a-11)
We move all terms to the left:
-(3-2a)-(3(a-11))=0
We add all the numbers together, and all the variables
-(-2a+3)-(3(a-11))=0
We get rid of parentheses
2a-(3(a-11))-3=0
We calculate terms in parentheses: -(3(a-11)), so:
3(a-11)
We multiply parentheses
3a-33
Back to the equation:
-(3a-33)
We get rid of parentheses
2a-3a+33-3=0
We add all the numbers together, and all the variables
-1a+30=0
We move all terms containing a to the left, all other terms to the right
-a=-30
a=-30/-1
a=+30

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