-(3-2n)+7=3(n+3)

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Solution for -(3-2n)+7=3(n+3) equation: 



-(3-2n)+7=3(n+3)

We move all terms to the left:

-(3-2n)+7-(3(n+3))=0

We add all the numbers together, and all the variables

-(-2n+3)-(3(n+3))+7=0

We get rid of parentheses

2n-(3(n+3))-3+7=0



We calculate terms in parentheses: -(3(n+3)), so:

3(n+3)

We multiply parentheses

3n+9

Back to the equation:

-(3n+9)



We add all the numbers together, and all the variables

2n-(3n+9)+4=0

We get rid of parentheses

2n-3n-9+4=0

We add all the numbers together, and all the variables

-1n-5=0

We move all terms containing n to the left, all other terms to the right

-n=5

n=5/-1

n=-5

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