-(3-r)+12=13

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Solution for -(3-r)+12=13 equation: 



-(3-r)+12=13

We move all terms to the left:

-(3-r)+12-(13)=0

We add all the numbers together, and all the variables

-(-1r+3)+12-13=0

We add all the numbers together, and all the variables

-(-1r+3)-1=0

We get rid of parentheses

1r-3-1=0

We add all the numbers together, and all the variables

r-4=0

We move all terms containing r to the left, all other terms to the right

r=4

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