-(3-y)+3=2(6+2y)

Solution for -(3-y)+3=2(6+2y) equation:

-(3-y)+3=2(6+2y)

We move all terms to the left:

-(3-y)+3-(2(6+2y))=0

We add all the numbers together, and all the variables

-(-1y+3)-(2(2y+6))+3=0

We get rid of parentheses

1y-(2(2y+6))-3+3=0


We calculate terms in parentheses: -(2(2y+6)), so:

2(2y+6)

We multiply parentheses

4y+12

Back to the equation:

-(4y+12)


We add all the numbers together, and all the variables

y-(4y+12)=0

We get rid of parentheses

y-4y-12=0

We add all the numbers together, and all the variables

-3y-12=0

We move all terms containing y to the left, all other terms to the right

-3y=12

y=12/-3

y=-4