-(3/4)(-2x)(3/4)(0.2y)(0)

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Solution for -(3/4)(-2x)(3/4)(0.2y)(0) equation:


x in (-oo:+oo)

-(-2*0*0.2*(3/4)*(3/4)*x*y) = 0

0 = 0

-2*0*0.2*(3/4)*(3/4)*x = 0

0 = 0

-2*0*0.2*(3/4)*(3/4) = 0

0 = 0

-2*0*0.2*(3/4) = 0

0 = 0

-2*0*0.2 = 0

0 = 0

-2*0 = 0

0 = 0

-2*0 = 0 <=> -2 = 0 or -2*0 = 0 <=> 0 = 0

-2*0*0.2 = 0 <=> -2*0 = 0 or -2*0*0.2 = 0 <=> 0.2 = 0

3/4 = 0

3/4 = 0

x belongs to the empty set

-2*0*0.2*(3/4) = 0 <=> -2*0*0.2 = 0 or -2*0*0.2*(3/4) = 0 <=> 3/4 = 0

3/4 = 0

3/4 = 0

x belongs to the empty set

-2*0*0.2*(3/4)*(3/4) = 0 <=> -2*0*0.2*(3/4) = 0 or -2*0*0.2*(3/4)*(3/4) = 0 <=> 3/4 = 0

x = 0

-2*0*0.2*(3/4)*(3/4)*x = 0 <=> -2*0*0.2*(3/4)*(3/4) = 0 or -2*0*0.2*(3/4)*(3/4)*x = 0 <=> x = 0

y = 0

x należy do R

-(-2*0*0.2*(3/4)*(3/4)*x*y) = 0 <=> -2*0*0.2*(3/4)*(3/4)*x = 0 or -(-2*0*0.2*(3/4)*(3/4)*x*y) = 0 <=> y = 0

x in (-oo:+oo)

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