-(3/4)(-x+8)=(1/2)(6x-10)

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Solution for -(3/4)(-x+8)=(1/2)(6x-10) equation:



-(3/4)(-x+8)=(1/2)(6x-10)
We move all terms to the left:
-(3/4)(-x+8)-((1/2)(6x-10))=0
Domain of the equation: 4)(-x+8)!=0
x∈R
Domain of the equation: 2)(6x-10))!=0
x∈R
We add all the numbers together, and all the variables
-(+3/4)(-1x+8)-((+1/2)(6x-10))=0
We multiply parentheses ..
-(-3x^2+3/4*8)-((+1/2)(6x-10))=0
We calculate fractions
(-(-3x^2+3*2)(6x-10)))/64x^2+()/64x^2=0
We can not solve this equation

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