-(3/4)p+6=12

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Solution for -(3/4)p+6=12 equation: 



-(3/4)p+6=12

We move all terms to the left:

-(3/4)p+6-(12)=0



Domain of the equation: 4)p!=0

p!=0/1

p!=0

p∈R



We add all the numbers together, and all the variables

-(+3/4)p+6-12=0

We add all the numbers together, and all the variables

-(+3/4)p-6=0

We multiply parentheses

-3p^2-6=0

a = -3; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·(-3)·(-6)
Δ = -72
Delta is less than zero, so there is no solution for the equation

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