-(3a+b)(4a-c)=

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Solution for -(3a+b)(4a-c)= equation: 


Simplifying
-1(3a + b)(4a + -1c) = 0

Multiply (3a + b) * (4a + -1c)
-1(3a * (4a + -1c) + b(4a + -1c)) = 0
-1((4a * 3a + -1c * 3a) + b(4a + -1c)) = 0

Reorder the terms:
-1((-3ac + 12a2) + b(4a + -1c)) = 0
-1((-3ac + 12a2) + b(4a + -1c)) = 0
-1(-3ac + 12a2 + (4a * b + -1c * b)) = 0
-1(-3ac + 12a2 + (4ab + -1bc)) = 0

Reorder the terms:
-1(4ab + -3ac + 12a2 + -1bc) = 0
-1(4ab + -3ac + 12a2 + -1bc) = 0
(4ab * -1 + -3ac * -1 + 12a2 * -1 + -1bc * -1) = 0
(-4ab + 3ac + -12a2 + 1bc) = 0

Solving
-4ab + 3ac + -12a2 + 1bc = 0

Solving for variable 'a'.

The solution to this equation could not be determined.

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