-(3b+1)+(28b-8)=0

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Solution for -(3b+1)+(28b-8)=0 equation:


Simplifying
-1(3b + 1) + (28b + -8) = 0

Reorder the terms:
-1(1 + 3b) + (28b + -8) = 0
(1 * -1 + 3b * -1) + (28b + -8) = 0
(-1 + -3b) + (28b + -8) = 0

Reorder the terms:
-1 + -3b + (-8 + 28b) = 0

Remove parenthesis around (-8 + 28b)
-1 + -3b + -8 + 28b = 0

Reorder the terms:
-1 + -8 + -3b + 28b = 0

Combine like terms: -1 + -8 = -9
-9 + -3b + 28b = 0

Combine like terms: -3b + 28b = 25b
-9 + 25b = 0

Solving
-9 + 25b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 25b = 0 + 9

Combine like terms: -9 + 9 = 0
0 + 25b = 0 + 9
25b = 0 + 9

Combine like terms: 0 + 9 = 9
25b = 9

Divide each side by '25'.
b = 0.36

Simplifying
b = 0.36

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