-(3b+15)=-6(2b-2)

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Solution for -(3b+15)=-6(2b-2) equation: 



-(3b+15)=-6(2b-2)

We move all terms to the left:

-(3b+15)-(-6(2b-2))=0

We get rid of parentheses

-3b-(-6(2b-2))-15=0



We calculate terms in parentheses: -(-6(2b-2)), so:

-6(2b-2)

We multiply parentheses

-12b+12

Back to the equation:

-(-12b+12)



We get rid of parentheses

-3b+12b-12-15=0

We add all the numbers together, and all the variables

9b-27=0

We move all terms containing b to the left, all other terms to the right

9b=27

b=27/9

b=3

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