-(3b-1)-2(2b-2)+5(-b-3)=

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Solution for -(3b-1)-2(2b-2)+5(-b-3)= equation:


-(3b-1)-2(2b-2)+5(-b-3)=0

We simplify the equation to the form, which is simple to understand 
-(3b-1)-2(2b-2)+5(-b-3)=0

Remove unnecessary parentheses
-3b+1-2*(2b-2)+5*(-b-3)=0

Reorder the terms in parentheses
-3b+1+(-4b+4)+5*(-b-3)=0

Remove unnecessary parentheses
-3b+1-4b+4+5+*(-b-3+)=0

Reorder the terms in parentheses
-3b+1-4b+4+(-5b-15)=0

Remove unnecessary parentheses
-3b+1-4b+4-5b-15=0

We move all terms containing b to the left and all other terms to the right. 
-3b-4b-5b=0-1-4+15

We simplify left and right side of the equation. 
-12b=+10

We divide both sides of the equation by -12 to get b. 
b=-0.83333333333333

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