-(3b-12)=60

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Solution for -(3b-12)=60 equation: 



-(3b-12)=60

We move all terms to the left:

-(3b-12)-(60)=0

We get rid of parentheses

-3b+12-60=0

We add all the numbers together, and all the variables

-3b-48=0

We move all terms containing b to the left, all other terms to the right

-3b=48

b=48/-3

b=-16

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