-(3b-15)=6(2b+4)+6

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Solution for -(3b-15)=6(2b+4)+6 equation: 



-(3b-15)=6(2b+4)+6

We move all terms to the left:

-(3b-15)-(6(2b+4)+6)=0

We get rid of parentheses

-3b-(6(2b+4)+6)+15=0



We calculate terms in parentheses: -(6(2b+4)+6), so:

6(2b+4)+6

We multiply parentheses

12b+24+6

We add all the numbers together, and all the variables

12b+30

Back to the equation:

-(12b+30)



We get rid of parentheses

-3b-12b-30+15=0

We add all the numbers together, and all the variables

-15b-15=0

We move all terms containing b to the left, all other terms to the right

-15b=15

b=15/-15

b=-1

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