-(3b-15)=6(2b-5)

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Solution for -(3b-15)=6(2b-5) equation: 



-(3b-15)=6(2b-5)

We move all terms to the left:

-(3b-15)-(6(2b-5))=0

We get rid of parentheses

-3b-(6(2b-5))+15=0



We calculate terms in parentheses: -(6(2b-5)), so:

6(2b-5)

We multiply parentheses

12b-30

Back to the equation:

-(12b-30)



We get rid of parentheses

-3b-12b+30+15=0

We add all the numbers together, and all the variables

-15b+45=0

We move all terms containing b to the left, all other terms to the right

-15b=-45

b=-45/-15

b=+3

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