-(3b-2)+2(4b-2)=6-b

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Solution for -(3b-2)+2(4b-2)=6-b equation: 



-(3b-2)+2(4b-2)=6-b

We move all terms to the left:

-(3b-2)+2(4b-2)-(6-b)=0

We add all the numbers together, and all the variables

-(3b-2)+2(4b-2)-(-1b+6)=0

We multiply parentheses

-(3b-2)+8b-(-1b+6)-4=0

We get rid of parentheses

-3b+8b+1b+2-6-4=0

We add all the numbers together, and all the variables

6b-8=0

We move all terms containing b to the left, all other terms to the right

6b=8

b=8/6

b=1+1/3

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