-(3k+5)+8k=4(1-k)

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Solution for -(3k+5)+8k=4(1-k) equation: 



-(3k+5)+8k=4(1-k)

We move all terms to the left:

-(3k+5)+8k-(4(1-k))=0

We add all the numbers together, and all the variables

-(3k+5)+8k-(4(-1k+1))=0

We add all the numbers together, and all the variables

8k-(3k+5)-(4(-1k+1))=0

We get rid of parentheses

8k-3k-(4(-1k+1))-5=0



We calculate terms in parentheses: -(4(-1k+1)), so:

4(-1k+1)

We multiply parentheses

-4k+4

Back to the equation:

-(-4k+4)



We add all the numbers together, and all the variables

5k-(-4k+4)-5=0

We get rid of parentheses

5k+4k-4-5=0

We add all the numbers together, and all the variables

9k-9=0

We move all terms containing k to the left, all other terms to the right

9k=9

k=9/9

k=1

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