-(3x+4)+2x=4(2x-3)-10

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Solution for -(3x+4)+2x=4(2x-3)-10 equation: 



-(3x+4)+2x=4(2x-3)-10

We move all terms to the left:

-(3x+4)+2x-(4(2x-3)-10)=0

We add all the numbers together, and all the variables

2x-(3x+4)-(4(2x-3)-10)=0

We get rid of parentheses

2x-3x-(4(2x-3)-10)-4=0



We calculate terms in parentheses: -(4(2x-3)-10), so:

4(2x-3)-10

We multiply parentheses

8x-12-10

We add all the numbers together, and all the variables

8x-22

Back to the equation:

-(8x-22)



We add all the numbers together, and all the variables

-1x-(8x-22)-4=0

We get rid of parentheses

-1x-8x+22-4=0

We add all the numbers together, and all the variables

-9x+18=0

We move all terms containing x to the left, all other terms to the right

-9x=-18

x=-18/-9

x=+2

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