-(3x+4)+8=2x+12-x

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Solution for -(3x+4)+8=2x+12-x equation: 



-(3x+4)+8=2x+12-x

We move all terms to the left:

-(3x+4)+8-(2x+12-x)=0

We add all the numbers together, and all the variables

-(3x+4)-(x+12)+8=0

We get rid of parentheses

-3x-x-4-12+8=0

We add all the numbers together, and all the variables

-4x-8=0

We move all terms containing x to the left, all other terms to the right

-4x=8

x=8/-4

x=-2

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