-(3x-1)/3-2(x-8)/5=(x+8)/5-3

Solution for -(3x-1)/3-2(x-8)/5=(x+8)/5-3 equation:

-(3x-1)/3-2(x-8)/5=(x+8)/5-3

We move all terms to the left:

-(3x-1)/3-2(x-8)/5-((x+8)/5-3)=0

We calculate fractions


(-(3x-1)*5*5)/()+(-6x+48)/()+(-((x+8)*3)/()=0


We calculate terms in parentheses: +(-(3x-1)*5*5)/(), so:

-(3x-1)*5*5)/(

We multiply all the terms by the denominator


-(3x-1)*5*5)

We get rid of parentheses

-3x+1)*5*5

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)



We calculate terms in parentheses: +(-((x+8)*3)/(), so:

-((x+8)*3)/(

We multiply all the terms by the denominator


-((x+8)*3)


We calculate terms in parentheses: -((x+8)*3), so:

(x+8)*3

We multiply parentheses

3x+24

Back to the equation:

-(3x+24)


We get rid of parentheses

-3x-24

Back to the equation:

+(-3x-24)


We get rid of parentheses

-3x+(-6x+48)/()-3x-24=0

We multiply all the terms by the denominator


-3x*()+(-6x+48)-3x*()-24*()=0

We add all the numbers together, and all the variables

-3x*()+(-6x+48)-3x*()=0

We get rid of parentheses

-3x*()-6x-3x*()+48=0

We add all the numbers together, and all the variables

-6x-3x*()-3x*()+48=0

We move all terms containing x to the left, all other terms to the right

-6x-3x*()-3x*()=-48