-(3x-1)/3-2(x-8)/5=(x+8)/5-3

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Solution for -(3x-1)/3-2(x-8)/5=(x+8)/5-3 equation:



-(3x-1)/3-2(x-8)/5=(x+8)/5-3
We move all terms to the left:
-(3x-1)/3-2(x-8)/5-((x+8)/5-3)=0
We calculate fractions
(-(3x-1)*5*5)/()+(-6x+48)/()+(-((x+8)*3)/()=0
We calculate terms in parentheses: +(-(3x-1)*5*5)/(), so:
-(3x-1)*5*5)/(
We multiply all the terms by the denominator
-(3x-1)*5*5)
We get rid of parentheses
-3x+1)*5*5
We add all the numbers together, and all the variables
-3x
Back to the equation:
+(-3x)
We calculate terms in parentheses: +(-((x+8)*3)/(), so:
-((x+8)*3)/(
We multiply all the terms by the denominator
-((x+8)*3)
We calculate terms in parentheses: -((x+8)*3), so:
(x+8)*3
We multiply parentheses
3x+24
Back to the equation:
-(3x+24)
We get rid of parentheses
-3x-24
Back to the equation:
+(-3x-24)
We get rid of parentheses
-3x+(-6x+48)/()-3x-24=0
We multiply all the terms by the denominator
-3x*()+(-6x+48)-3x*()-24*()=0
We add all the numbers together, and all the variables
-3x*()+(-6x+48)-3x*()=0
We get rid of parentheses
-3x*()-6x-3x*()+48=0
We add all the numbers together, and all the variables
-6x-3x*()-3x*()+48=0
We move all terms containing x to the left, all other terms to the right
-6x-3x*()-3x*()=-48

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