-(3x-2)=6(4+2x)

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Solution for -(3x-2)=6(4+2x) equation: 



-(3x-2)=6(4+2x)

We move all terms to the left:

-(3x-2)-(6(4+2x))=0

We add all the numbers together, and all the variables

-(3x-2)-(6(2x+4))=0

We get rid of parentheses

-3x-(6(2x+4))+2=0



We calculate terms in parentheses: -(6(2x+4)), so:

6(2x+4)

We multiply parentheses

12x+24

Back to the equation:

-(12x+24)



We get rid of parentheses

-3x-12x-24+2=0

We add all the numbers together, and all the variables

-15x-22=0

We move all terms containing x to the left, all other terms to the right

-15x=22

x=22/-15

x=-1+7/15

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