-(3x-3)-(2x-5)+4=-5(x1)-(3x+2)+3

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Solution for -(3x-3)-(2x-5)+4=-5(x1)-(3x+2)+3 equation: 



-(3x-3)-(2x-5)+4=-5(x1)-(3x+2)+3

We move all terms to the left:

-(3x-3)-(2x-5)+4-(-5(x1)-(3x+2)+3)=0

We get rid of parentheses

-3x-2x-(-5x1-(3x+2)+3)+3+5+4=0



We calculate terms in parentheses: -(-5x1-(3x+2)+3), so:

-5x1-(3x+2)+3

We add all the numbers together, and all the variables

-5x-(3x+2)+3

We get rid of parentheses

-5x-3x-2+3

We add all the numbers together, and all the variables

-8x+1

Back to the equation:

-(-8x+1)



We add all the numbers together, and all the variables

-5x-(-8x+1)+12=0

We get rid of parentheses

-5x+8x-1+12=0

We add all the numbers together, and all the variables

3x+11=0

We move all terms containing x to the left, all other terms to the right

3x=-11

x=-11/3

x=-3+2/3

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